4b+10b^2=0

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Solution for 4b+10b^2=0 equation: 



4b+10b^2=0

a = 10; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·10·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$


$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*10}=\frac{-8}{20}
=-2/5
$


$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*10}=\frac{0}{20}
=0
$

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